10 May, 2010

SQL Query to find out who attended office on Saturday

SQL Query to find out who attended office on Saturday:
A client of mine had a report requirement to find out the employees who attended office on Saturday in the last 30 days and their Check-In Check-Out times.
Here is some sample data that does that. For convenience, I have not added the CheckOut time, but hopefully you will get the idea
SAMPLE Data
DECLARE @TT TABLE (EID int, CheckIn DATETIME)
INSERT INTO @TT VALUES (2, 'April 02, 2010 11:25am')
INSERT INTO @TT VALUES (4, 'April 03, 2010 9:55am')
INSERT INTO @TT VALUES (5, 'April 07, 2010 11:24am')
INSERT INTO @TT VALUES (2, 'April 10, 2010 11:22am')
INSERT INTO @TT VALUES (3, 'April 15, 2010 5:27am')
INSERT INTO @TT VALUES (6, 'April 16, 2010 8:21am')
INSERT INTO @TT VALUES (7, 'April 17, 2010 11:55am')
INSERT INTO @TT VALUES (3, 'April 22, 2010 10:16am')
INSERT INTO @TT VALUES (4, 'April 24, 2010 11:35am')
INSERT INTO @TT VALUES (7, 'April 30, 2010 9:49pm')
INSERT INTO @TT VALUES (2, 'May 01, 2010 9:49am')
INSERT INTO @TT VALUES (5, 'May 02, 2010 10:43am')
INSERT INTO @TT VALUES (3, 'May 03, 2010 11:29am')
QUERY
SELECT * FROM @TT
WHERE DATENAME(weekday, CheckIn) = 'SATURDAY'
AND DATEDIFF(DD, CheckIn, GETDATE()) < 30
OUTPUT
Find Saturday
Hopefully these people get the bonus they deserve!

2 comments:

  1. Good amit .

    but

    SELECT * FROM @TT
    WHERE DATENAME(weekday, CheckIn) = 'SATURDAY'
    AND DATEDIFF(DD, CheckIn, GETDATE()) < 30
    what is ---> dd..?

    ReplyDelete
  2. Hi Saurabh

    Here dd is a datepart for which we are calling the function
    in
    DATEDIFF(DD, CheckIn, GETDATE())

    Datediff function calculate date difference on the basis of Day(DD)

    There are so many ather dateparts also supported by sql server
    check the list of those here

    ReplyDelete

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